Answer: B)792
Step-by-step explanation:
Given: The number of people in basketball team = 12
To choose different five-person starting lineups , we will use combinations.
The number of different five-person starting lineups can be chosen will be given by :-
[tex]^{12}C_5=\frac{12!}{(12-5)!5!}............[^nC_r=\frac{n!}{(n-r)!r!}}]\\=\frac{12\times11\times10\times9\times8\times7!}{7!\times5!}\\\\=\frac{12\times11\times10\times9\times8}{120}=792[/tex]
Hence, 792 different five-person starting lineups can be chosen .
