Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 23
and DC = 4, what is the length of BC in simplest radical form? (Note: the figure i
not drawn to scale.)

We can find the length of AB using the principle of similar triangles on the triangles ABD and ABC. We would also engage the use of trigonometrical ratios which may be expressed in the form SOA CAH TOA Where,

SOA stands for

Sin Ф = opposite side/hypotenuses side

Cosine Ф = adjacent side/hypotenuses side

Tangent Ф = opposite side/adjacent side

Considering triangle ABD, given that AD = 5 then

Cos A = AD/AB

Also,

Cos A = AB/AC

Given that AD = 5, AC = 13, AB = x

therefore,

x/13 = 5/x

x² = 65

x = √65

= 8.06

i hope its good

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 23 and DC = 4, what is the length of BC in simplest radical form? (Note: the figure i not drawn to scale.)

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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 23
and DC = 4, what is the length of BC in simplest radical form? (Note: the figure i
not drawn to scale.)