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A juggler has a bag containing three yellow balls, five green balls, four blue balls, and one red ball, all the same size. The juggler pulls a ball from the bag at random. Then, without replacing it, he pulls out a second ball. What is the probability that the juggler first draws a green ball followed by a blue ball?

Respuesta :

shoopdawhoopdedo
3 yellow + 5 green + 4 blue + 1 red = 13 total

Probability green: [tex] \frac{5 Green}{13 Total} [/tex]
Probability blue: [tex] \frac{4 Blue}{12 Total} [/tex]

Probability green then blue: [tex] \frac{5 Green}{13 Total} [/tex] x [tex] \frac{4 Blue}{12 Total} [/tex] = [tex] \frac{20}{156} = \frac{5}{39} [/tex]

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