5.the temperature of a sample of water increases from 20°c to 46.6°c as it absorbs 5650 calories of heat. what is the mass of the sample? (specific heat of water is 1.0 cal/g °c)

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[tex]Q=cm \Delta T \ \ \ \Rightarrow \ \ \ m=\frac{Q}{c \Delta T}\\\\ Q=5650cal\\ c=1\frac{cal}{g^{o}C}\\ \Delta T=46,6^{o}C-20^{o}C=26,6^{o}C\\\\ m=\frac{5650cal}{1\frac{cal}{g^{o}C}*26,6^{o}C}\approx 212,41g[/tex]