In this question , we have to use sine law, which is
[tex] \frac{sin \ Q}{PR} = \frac{sin \ P}{QR} [/tex]
[tex] \frac{sin73}{68} = \frac{sin \ P }{47.6} [/tex]
[tex] sin \ P = \frac{47.6 sin 73}{68} [/tex]
[tex] P = sin^{-1} ( \frac{ 47.6 sin73}{68}) = 42 [/tex]
Correct option is b.
