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Ammonia reacts with oxygen according to the equation 4NH3(g)+5O2(g)→4NO(g)+6H2O(g),ΔHrxn=−906 kJ Calculate the heat (in kJ) associated with the complete reaction of 155 g of NH3.

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Dejanras
Answer is: 2065.15 kJ.
Balanced chemical reaction: 4NH₃ + 5O₂ → 4NO + 6H₂O, ΔHrxn=−906 kJ.
m(NH₃) = 155 g.
n(NH₃) = m(NH₃) ÷ M(NH₃).
n(NH₃) = 155 g ÷ 17 g/mol.
n(NH₃) = 9.118 mol.
Make proportion: 4 mol(NH₃) : 906 kJ = 9.118 mol : Q.
Q = 906 kJ · 9.118 mol / 4 mol.
Q = 2065.15 kJ.

Answer:

-956 kJ

Explanation:

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