Respuesta :

znk

d. 0.0166 mol/L

Step 1. Write the balanced chemical equation

2H3PO4 + 3Ba(OH)2 → Ba3(PO4)2 + 6H2O

Step 2. Calculate the moles of Ba(OH)2

Moles of Ba(OH)2  = 876 mL Ba(OH)2  x [0.0102 mmol Ba(OH)2 /1 mL Ba(OH)2] = 8.935 mmol Ba(OH)2

Step 3. Calculate the moles of H3PO4

Moles of H3PO4 = 8.935 mmol Ba(OH)2  x (2 mmol H3PO4/3 mmol Ba(OH)2) = 5.957 mmol H3PO4

Step 4. Calculate the molar concentration of the H3PO4

c = moles/litres = 5.957 mmol /358 mL = 0.0166 mol/L