Answer: Maximum area would be 225 sq. yard.
Step-by-step explanation:
Since we have given that
Perimeter of rectangular pig sty = 60 yd
As we know the formula for "Perimeter ":
[tex]60=2(l+b)\\\\\dfrac{60}{2}=l+b\\\\30=l+b[/tex]
Since we need the maximum area she can enclose:
Square with same perimeter would enclose maximum area than the rectangle.
For this we assume l=b.
So, it becomes,
[tex]30=l+l\\\\30=2l\\\\\dfrac{30}{2}=l\\\\15\ yd=l[/tex]
So, Maximum area would be
[tex]Side\times Side\\\\=Side^2\\\\=15^2\\\\=225\ sq.\ yard[/tex]
Hence, the maximum area would be 225 sq. yard.
