Use the drawing tool(s) to form the correct answer on the provided graph.

Consider the function below.

h(x) = x^{2] - 2x - 8

Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of the function.

x-intercept (s):
For this case h (x) = 0
x2 - 2x - 8 = 0
(x-4) * (x + 2) = 0
x1 = 4
x2 = -2
y-intercept:
For this case x = 0
h (0) = (0)2 - 2 (0) - 8
h (0) = - 8
vertex:
We derive the equation:
h '(x) = x2 - 2x - 8
h (x) = 2x - 2
We match zero:
2x-2 = 0
x = 2/2
x = 1
We evaluate the function for x = 1
h (1) = (1)2 - 2 (1) - 8
h (1) = 1 - 2 - 8
h (1) = -9
The vertex is:
(1, -9)
axis of symmetry of the function:
x = 1

Professor1994 Professor1994 · Answer 2 · 2018-04-12T12:56:30+02:00

Professor1994 Professor1994

12-04-2018

Hello,
Please, see the attached files.
Thanks.

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Use the drawing tool(s) to form the correct answer on the provided graph. Consider the function below. h(x) = x^{2] - 2x - 8 Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of the function.

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Use the drawing tool(s) to form the correct answer on the provided graph.

Consider the function below.

h(x) = x^{2] - 2x - 8

Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of the function.