Respuesta :
To solve this, you need to subtract 28 from both sides, then solve.
y=x^2+3x-28
The x-intercepts are (-7,0) and (4,0)
y=x^2+3x-28
The x-intercepts are (-7,0) and (4,0)
Answer: The required x-intercepts are (4, 0) and (-7, 0).
Step-by-step explanation: We are given to find the x-intercepts for the parabola defined by the following equation :
[tex]y=x^2+3x-28~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We know that
the x-intercepts of a function are the points where the y co-ordinate is zero.
So, from equation (i), we have
[tex]y=0\\\\\Rightarrow x^2+3x-28=0\\\\\Rightarrow x^2+7x-4x-28=0\\\\\Rightarrow x(x+7)-4(x+5)=0\\\\\Rightarrow (x-4)(x+7)=0\\\\\Rightarrow x-4=0,~~~x+7=0\\\\\Rightarrow x=4,~-7.[/tex]
Therefore, the x-intercepts of the given function are (4, 0) and (-7, 0).
