Let's call: a = price of 1 apple p = price of 1 peach
The total cost is the price of 1 apple times the number of apples plus the price of 1 peach times the number of peaches, therefore the system can be: [tex] \left \{ {{6a + 9p = 7.86} \atop {4a + 5p = 4.82}} \right. [/tex]
Solve for a in the second equation (you can choose to solve for any of the variables in any of the equations, try to understand what is the best): a = (4.82 - 5p) / 4
Now, substitute in the first equation: 6 · (4.82 - 5p) / 4 + 9p = 7.86 7.23 - (15/2)p + 9p = 7.86 (3/2)p = 0.63 p = 0.42
Now, substitute this value in the formula found for a: a = (4.82 - 5·0.42) / 4 = 0.68
Therefore, one apple costs 0.68$ and one peach costs 0.42$.
