Respuesta :
The upper bound would be 3.16.
We find the standard error by dividing the standard deviation by the square root of the sample size:
[tex]\frac{\sigma}{\sqrt{n}}=\frac{2.26}{\sqrt{504}}=\frac{2.26}{22.45}=0.10[/tex]
To calculate the margin of error, we multiply the standard error by 2:
0.1(2) = 0.2
For the upper bound, we add this to the mean:
2.96+0.2 = 3.16
We find the standard error by dividing the standard deviation by the square root of the sample size:
[tex]\frac{\sigma}{\sqrt{n}}=\frac{2.26}{\sqrt{504}}=\frac{2.26}{22.45}=0.10[/tex]
To calculate the margin of error, we multiply the standard error by 2:
0.1(2) = 0.2
For the upper bound, we add this to the mean:
2.96+0.2 = 3.16
The upper bound of a 95% confidence interval if the sample mean is 2.96 is 3.16.and this can be determined by using the formula of standard error and margin of error.
Given :
- Assuming that a sample (n = 504) has a sample standard deviation of 2.26.
- 95% confidence interval.
- The sample mean is 2.96.
First, evaluate the standard error by using the below formula:
[tex]\rm SE = \dfrac{\sigma}{\sqrt{n} }[/tex]
Now, put the values of n and [tex]\sigma[/tex] in the above equation in order to determine the standard error.
[tex]\rm SE = \dfrac{2.26}{\sqrt{506} }[/tex]
SE = 0.10
In order to determine the margin of error multiplies the standard error by 2.
ME = 0.1 [tex]\times[/tex] 2
ME = 0.20
Now, add the margin of error and the sample mean in order to evaluate the upper bound.
= 2.96 + 0.20b
= 3.16
The upper bound of a 95% confidence interval if the sample mean is 2.96 is 3.16.
For more information, refer to the link given below:
https://brainly.com/question/25436087
