If the sin 60° = square root of three over two, then which statement is true? (6 points)

cos 30° = square root of three over two, because the cosine and sine are complements
cos 30° = 0, because the cosine and sine are complements
cos 120° = square root of three over two, because the cosine and sine are supplements
cos 120° = 0, because the cosine and sine are supplements

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JumpingBobcat JumpingBobcat · Answer 1 · 2018-03-12T01:00:46+01:00

The first one, which states that cos(30 deg) are complements

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ColinJacobus ColinJacobus · Answer 2 · 2019-02-24T16:33:33+01:00

Answer: The answer is (a) cos 30° = square root of three over two, because the cosine and sine are complements

Step-by-step explanation: Given that -

[tex]\sin 60^\circ=\dfrac{\sqrt 3}{2}.[/tex]

we are to select the correct statement from the given four options.

We know that sine and cosine functions are supplement of each other. So, we have

[tex]\sin 60^\circ=\cos(90^\circ-60^\circ)=\cos 30^\circ=\dfrac{\sqrt 3}{2}.[/tex]

Thus, the correct option is (a) cos 30° = square root of three over two, because the cosine and sine are complements.