A line has a slope of - 3/5. Which ordered pairs could be points on a parallel line? Check all that apply.

A). (–8, 8) and (2, 2)
B). (–5, –1) and (0, 2)
C). (–3, 6) and (6, –9)
D). (–2, 1) and (3, –2)
E). (0, 2) and (5, 5)

I think it's A, but I'm not sure. Please help, I'll pick Brainliest! :-P

In order to find this, we must find the full value of the equation using one of the points and the slope. This will allow us to find the y-intercept. We'll use the (-2, 1) point to start.

y = mx + b

1 = -3/5(-2) + b

1 = 6/5 + b

-1/5 = b

This y-intercept gives us the overall equation of y = -3/5x - 1/5. Now we can try the other point in the equation to see if it works as well.

y = -3/5x - 1/5

-2 = -3/5(3) - 1/5

-2 = -9/5 - 1/5

-2 = -10/5

-2 = -2 (TRUE)

Since this works in the equation, we know that D is the correct answer.

Anshuyadav Anshuyadav · Answer 2 · 2022-07-01T05:28:01+02:00

The ordered pairs will be the points on the parallel line are

(-8, 8) and (2, 2)

(-2, 1) and (3, -2)

What is the slope of a line?

A slope of a line is the change in y coordinate with respect to the change in x coordinate.

How to find the slope of line from the two points?

If [tex](x_{1} ,y_{1} )[/tex] and [tex](x_{2} , y_{2} )[/tex] be the two points then the slope of the line is given by

[tex]slope = \frac{y_{2} -y_{1} }{x_{2}-x_{1} }[/tex]

According to the given question.

We have slope of a line is [tex]\frac{-3}{5}[/tex].

As, we know that the two parallel lines have the same slope.

Now according to the given ordered pairs

A). (-8, 8) and (2, 2)

[tex]slope = \frac{2-8}{2+8} = \frac{-6}{10} =\frac{-3}{5}[/tex]

Therefore, (-8, 8) and (2, 2) are the ordered pairs could be the points on the parallel line.

B) (-5, -1) and (0, 2)

[tex]slope = \frac{2+1}{0+5} =\frac{3}{5} \neq \frac{-3}{5}[/tex]

Hence, the ordered pair (-5, -1) and (0, 2) will never be the points on the parallel line.

C) (-3, 6) and (6, -9)

[tex]slope = \frac{-9-6}{6+3} =\frac{-15}{9} =\frac{-5}{3}\neq \frac{-3}{5}[/tex]

The ordered pair (-3, 6) and (6, -9) will never be the points on the parallel line.

D). (-2, 1) and (3, -2)

[tex]slope = \frac{-2-1}{3+2} =\frac{-3}{5}[/tex]

Therefore, (-2, 1) and (3, -2) are the ordered pairs could be the points on the parallel line.

E). (0, 2) and (5, 5)

[tex]slope = \frac{5-2}{5-0} =\frac{3}{5} \neq \frac{-3}{5}[/tex]

Therefore, (0, 2) and (5, 5) are the ordered pairs could not be the points on the parallel line.

Hence, the ordered pairs will be the points on the parallel line are

(-8, 8) and (2, 2)

(-2, 1) and (3, -2)

Find out more information about slope of lines here:

https://brainly.com/question/14511992

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