Answer:
[tex]\text{The solution set is }\{\frac{-1}{4}, \frac{1}{2}\}[/tex]
Step-by-step explanation:
Given the equation
[tex]8x^2-2x=1[/tex]
we have to find the solution of above equation.
Expression: [tex]8x^2-2x=1[/tex]
[tex]8x^2-2x-1=0[/tex]
[tex]8x^2-4x+2x-1=0[/tex]
[tex]4x(2x-1)+1(2x-1)=0[/tex]
[tex](4x+1)(2x-1)=0[/tex]
[tex]x=\frac{-1}{4}, \frac{1}{2}[/tex]
[tex]\text{The solution set is }\{\frac{-1}{4}, \frac{1}{2}\}[/tex]
Option B is correct
