Respuesta :

Atrey
[tex]x^2+5x+9 [/tex]

The polynomial cannot be factored with rational numbers due to b being 5. You can factor it if b is equal to 6.

None
jcherry99
They are not real.
b^2 - 4ac =
b = 5
a = 1
c = 9
5^2 - 4(1)(9)
25 - 36
- 11
The quadratic formula is
x = (- b) +/- sqrt(b^2 - 4ac)
. . . . .==============
. . . . . . . . . . 2(a)
x = ( (- 5 +/- sqrt(-11) ) / 2
x = ( - 2.5 +/- sqrt(11) i / 2