That structure would be the Sphere.
With a Volume of V = 4/3*π*r**3
And a surface area of A = 4*π*r**2
r =(A/(4*π))**1/2
V = 4/3*π* [A^(3/2)/(8 π^(3/2))] = A^(3/2)/(6 sqrt(π))
We can graph V in tems of A
And compare it to the graph y = x
We can see that the Volume increases more rapidly compared to the Area
