carolynalee
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Sarah used her calculator to find sin 125°. She wrote down sin 125° = -.57. How could Sarah recognize that her answer is incorrect?

Respuesta :

sin125, on the unit circle, should be positive(not negative), since it should be in quadrant two if the angle 125 degrees is in standard position.
Blacklash

Answer:

The angle is 125° which lies in second quadrant, where sine and co secant values are positive. Sarah found out sin 125° = -.57, which is negative, which is not possible.

Step-by-step explanation:

We have four quadrants, let positive x axis represent zero axis.

From 0° to 90° all trigonometric values are positive. Quadrant 1

From 90° to 180° only sine and co secant values are positive. Quadrant 2

From 180° to 270° only tangent and cotangent values are positive. Quadrant 3

From 270° to 360° only cosine and secant values are positive. Quadrant 4

Here the angle is 125° which lies in second quadrant, where sine and co secant values are positive. Sarah found out sin 125° = -.57, which is negative, which is not possible.

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