Respuesta :
100.
ppb of chcl3 in drinking water means 100 g of CHCl3 in 1,000,0000,000 g of water
Molarity, M
M = number of moles of solute / volume of solution in liters
number of moles of solute = mass of CHCl3 / molar mass of CHCl3
molar mass of CHCl3 = 119.37 g/mol
number of moles of solute = 100 g / 119.37 g/mol = 0.838 mol
using density of water = 1 g/ ml => 1,000,000,000 g = 1,000,000 liters
M = 0.838 / 1,000,000 = 8.38 * 10^ - 7 M <----- answer
Molality, m
m = number of moles of solute / kg of solvent
number of moles of solute = 0.838
kg of solvent = kg of water = 1,000,000 kg
m = 0.838 moles / 1,000,000 kg = 8.38 * 10^ - 7 m <----- answer
mole fraction of solute, X solute
X solute = number of moles of solute / number of moles of solution
number of moles of solute = 0.838
number of moles of solution = number of moles of solute + number of moles of solvent
number of moles of solvent = mass of water / molar mass of water = 1,000,000,000 g / 18.01528 g/mol = 55,508,435 moles
number of moles of solution = 0.838 moles + 55,508,435 moles = 55,508,436 moles
X solute = 0.838 / 55,508,435 = 1.51 * 10 ^ - 8 <------ answer
mass percent, %
% = (mass of solute / mass of solution) * 100 = (100g / 1,000,000,100 g) * 100 =
% = 10 ^ - 6 % <------- answer
Molarity, M
M = number of moles of solute / volume of solution in liters
number of moles of solute = mass of CHCl3 / molar mass of CHCl3
molar mass of CHCl3 = 119.37 g/mol
number of moles of solute = 100 g / 119.37 g/mol = 0.838 mol
using density of water = 1 g/ ml => 1,000,000,000 g = 1,000,000 liters
M = 0.838 / 1,000,000 = 8.38 * 10^ - 7 M <----- answer
Molality, m
m = number of moles of solute / kg of solvent
number of moles of solute = 0.838
kg of solvent = kg of water = 1,000,000 kg
m = 0.838 moles / 1,000,000 kg = 8.38 * 10^ - 7 m <----- answer
mole fraction of solute, X solute
X solute = number of moles of solute / number of moles of solution
number of moles of solute = 0.838
number of moles of solution = number of moles of solute + number of moles of solvent
number of moles of solvent = mass of water / molar mass of water = 1,000,000,000 g / 18.01528 g/mol = 55,508,435 moles
number of moles of solution = 0.838 moles + 55,508,435 moles = 55,508,436 moles
X solute = 0.838 / 55,508,435 = 1.51 * 10 ^ - 8 <------ answer
mass percent, %
% = (mass of solute / mass of solution) * 100 = (100g / 1,000,000,100 g) * 100 =
% = 10 ^ - 6 % <------- answer
Molarity :M = 8.368.10⁻⁷
molality = 8.368.10⁻⁷
mole fraction = 1.508 .10⁻⁸
mass percent = 10⁻⁵%
Further explanation
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. Concentration shows the amount of solute in a unit of the amount of solvent.
- Molality (m)
Molality shows how many moles are dissolved in every 1000 grams of solvent.
[tex]m=\frac{n}{p}[/tex]
m = Molality
n = number of moles of solute
p = solvent mass (1000 grams)
- Mole
Mole itself is the number of particles contained in a substance
amounting to 6.02.10 ^ 23
Mole can also be sought if the amount of substance mass and its molar mass is known
[tex]mole=\frac{mass}{molar mass}[/tex]
- Molarity (M)
Molarity is a way to express the density of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large {\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
ppb mean : part per billion or 1 : 10⁹, the convertion are :
- 1. molarity
1 ppm = 1 mg/l
1 ppm = 1000 ppb
1 ppb = 10⁻³ mg/l
100 ppb = 0.1 mg/l = 10⁻⁴ g/l
molar mass CHCl₃ = 12 + 1 + 35.5 .3 = 119.5 grams/mole
mole CHCl₃ = mass : molar mass
mole CHCl₃ = 10⁻⁴ g : 119.5
mole CHCl₃ = 8.368.10⁻⁷
Because the water(solvent) = 1 L, so the molarity :
M = mol : L
M = 8.368.10⁻⁷ : 1 L
M = 8.368.10⁻⁷
- 2. molality
mole CHCl₃ = 8.368.10⁻⁷
Solvent = 1 L = 1 Kg(ρ water = 1 g/ml or 1 kg/L)
molality = mole : 1 kg solvent
molality = 8.368.10⁻⁷ : 1
molality = 8.368.10⁻⁷
- 3. mole fraction
mole water = 1000 gr : 18 (molar mass H₂O)
mole water = 55.5
mole fraction = mole CHCl₃ : (mole H₂O + mole CHCl₃)
mole CHCl₃ is considered very small, then
mole fraction = mole CHCl₃ : mole H₂O
mole fraction = 8.368.10⁻⁷ : 55.5
mole fraction = 1.508 .10⁻⁸
- 4. mass percent
mass CHCl₃ = 10⁻⁴ grams
mass H₂O = 1000 grams
mass percent = mass CHCl₃ : (mass CHCl₃+mass H₂O) x 100%
mass CHCl₃ is considered very small, then
mass percent = (mass CHCl₃ : mass H₂O)x 100%
mass percent = 10⁻⁴ : 10³ x 100%
mass percent = 10⁻⁵%
Learn more
the molality of the solution
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Keywords: molality, molarity, mass percent, mole fraction
