contestada

Imagine adding electrons to the pin until the negative charge has the very large value 3.00 mc. how many electrons are added for every 109 electrons already present?

Respuesta :

shinmin
The formula for this problem would be this:
electrons added = Q /e = 3 x 10^-3 C / (1.6 x 10^- 19 C / electron) 
number of electrons added = 1.875 x 10^16 
1.875 x 10^16 / 2.62 x 10^24 = 7.156 x10^-9 
so 7.156 electrons for every 10^9 are already present.

Otras preguntas