On the coordinate grid of a map, Josie's house is located at ( 2 , 7 ). Her school is located at ( -5 , 5 ). If each map unit equals one mile, what is the approximate distance from her house to her school?
A) 2.83 miles
B) 4.79 miles
C) 7.28 miles
D) 12.37 miles

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calculista calculista · Answer 1 · 2019-03-03T02:34:39+01:00

Answer:

Option C. [tex]7.28\ miles[/tex]

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

Let

[tex]A(2,7)\\E(-5.5)[/tex]

substitute the values

[tex]d=\sqrt{(5-7)^{2}+(-5-2)^{2}}[/tex]

[tex]d=\sqrt{(-2)^{2}+(-7)^{2}}[/tex]

[tex]d=\sqrt{53}\ units[/tex]

Remember that

each map unit equals one mile

so

[tex]\sqrt{53}\ units=\sqrt{53}\ miles=7.28\ miles[/tex]

JeanaShupp JeanaShupp · Answer 2 · 2019-04-26T19:03:29+02:00

Answer: C) 7.28 miles

Step-by-step explanation:

Given: On the coordinate grid of a map, Josie's house is located at ( 2 , 7 ). Her school is located at ( -5 , 5 ).

Using distance formula ,distance between points (a,b) and (x,y) is :

[tex]d=\sqrt{(x-a)^2+(y-b)^2}[/tex]

Now, distance from her house to her school ia given by :-

[tex]d=\sqrt{(-5-2)^2+(5-7)^2}\\\\=\sqrt{(-7)^2+(-2)^2}\\\\=\sqrt{49+4}\\\\=\sqrt{53}=7.28010988928\approx7.28\text{ miles}[/tex]

Hence, the approximate distance from her house to her school = 7.28 miles