contestada

What is the force of attraction between Marvin (mass 50kg$ and his dog commander k-9 (mass 30kg) when they are 3 meters apart? Why is the five so small?

Respuesta :

((6.7*10^-11)*(50kg)(30kg))/(5m^2) I don’t got a calculator but there them numbers it’s like Newton’s gravitational equation or sum like that