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“A 90.0 kg person rides a spinning amusement park ride that has a radius of 11.5 m. If the person’s tangential speed is 13.2 m/s, what is the magnitude of the centripetal force acting on the person? ”

Respuesta :

Kalahira
Centripetal force = mass * centripetal acceleration. Centeipetal acceleration = (tangential speed )^2/ radius. So Centripetal acceleration a= v^2/ r = (13.2)^2/ 11.5 = 174.24/11.5 = 15.153 So Centripetal force = 90 * 15.1513 = 1363.77N

Answer : Centripetal force is 1363.6 N

Explanation :

It is given that,

Mass of the person, [tex]m=90\ kg[/tex]

Radius of the circular path, [tex]r=11.5\ m[/tex]

Person's tangential speed, [tex]v=13.2\ m/s[/tex]

Centripetal force acting on the person is :

[tex]F_c=\dfrac{mv^2}{r}[/tex]

[tex]F_c=\dfrac{90\ kg\times (13.2\ m/s)^2}{11.5\ m}[/tex]

[tex]F_c=1363.6\ N[/tex]

So, the centripetal force acting on the person is 1363.6 N

Hence, this is the required solution.

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