Use the quadratic equation:
[tex]x= \frac{-b +/- \sqrt{b^2-4ac} }{2a} [/tex]
Where a = 1, b = -2 and c = 2
So, x = (2 +/- √ [ (-2)^2 - 4 (1)(2) ] ) / 2(1)
x = [2 +/- √(4 -8)] / 2
x = [2 +/- √(-4) ] / 2 = (2 +/- 2i) / 2 = 1 +/- i
So, the soluttions are x = 1 + i and x = 1 - i.
Answer: 1 +/- i
