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A 3.677g sample of nac2h3o2 x 3h2o is heated until all the water molecules are gone. nac2h3o2 has mass of 2.216g left in the test tube. determine the ratio of moles of water to moles of nac2h3o2 in the original compound.

Respuesta :

scme1702
The mass of water is determined by calculating the difference in mass of the sample before and after the heating. 

Mass of water = 3.677 - 2.216
Mass of water = 1.461 g
Moles of water = 1.461 / 18 = 0.0812

Mass of NaC₂H₃O₂ = 2.216 g
Moles of NaC₂H₃O₂ = 2.216 / 82 = 0.0270

Molar ratio = 0.0812 / 0.0270 = 3.00

Therefore, there are 3 moles of water for every mole of NaC₂H₃O₂

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