Respuesta :
7. b - 2 - 3b = 4
-2b = 6
b = -3
a = -5
solution is (-5,-3) <==
8. multiply A by -4...this eliminates the z's when added <==
9. first error...step 2....he didn't distribute correctly <==
10. p = d + 2 : p = d - 1 <==
-2b = 6
b = -3
a = -5
solution is (-5,-3) <==
8. multiply A by -4...this eliminates the z's when added <==
9. first error...step 2....he didn't distribute correctly <==
10. p = d + 2 : p = d - 1 <==
Answer:
7.The solution to the set of equation in the form (-5,-3).
8.Multiply equation A by -4 used to eliminate the z- term.
9.Step 2: [tex]-4y=-16+8z[/tex] { equation A in step1 is simplified}.
10. [tex]p= d+2[/tex]
[tex]p=d-1[/tex].
Step-by-step explanation:
7. Two equation are given below:
[tex]a-3b=4[/tex]
[tex]a=b-2[/tex]
II eqaution can be write as
[tex]a-b=-2[/tex]
Subtracting equation II from equation I then we get
[tex]-2b=6[/tex]
By division property of equality
[tex]b=\frac{6}{-2}[/tex]
By simplification we get
[tex]b=-3[/tex]
Substitute the value of b in equation I then we get
[tex]a-3(-3)=4[/tex]
[tex]a+9=4[/tex]
[tex]a=4-9[/tex]
[tex]a=-5[/tex]
Hence, the solution of the set of equation is (-5,-3).
8. Equation A: [tex]x+z=6[/tex]
Equation B: [tex]2x+4z=1[/tex]
Equation A is multiplied by -4 then we get
Equation A:[tex]-4x-4z=-24[/tex]
Adding both equation A and B then we get
[tex]-2x=-23[/tex]
Answer: Multiply equation A by -4 to eliminate the z-term.
9.Equation A: [tex]y=4-2z[/tex]
Equation B:[tex]4y=2-4z[/tex]
Step1 :[tex]-4(y)=-4(4-2z)[/tex]
Equation A is multiplied by -4
[tex]4y=2-4z [/tex] [equation B]
Step 2: [tex]-4y=-16+8z[/tex]
[tex]4y=2-4z[/tex] [equation B]
Equation A in step1 s simplified .
Step3: [tex]0= -14+4z[/tex]
Equations in step 2 are added.
Step 4: [tex]4z=14[/tex]
Step5: [tex]z=\frac{7}{2}[/tex]
Hence, in step 2 student did make first an error.
10. Given
Variable p is more than variable d
We can write in algebraic expression
[tex]p=d+2[/tex]
Variable p is also 1 less than variable d.
Then the algebraic expression
[tex]p=d-1[/tex]
Hence, [tex]p=d+2[/tex]
[tex]p=d-1[/tex]