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A 2 kg ball is thrown upward with a velocity of 15 m/s. What is the kinetic energy of the ball as it is being thrown?

Respuesta :

KE=1/2 m v^2
KE= .5 x 2kg x 15m/s to the 2nd power
KE=225 km/s

Answer:

Kinetic energy = 225 J

Explanation:

As we know that kinetic energy is given as

[tex]KE = \frac{1}{2}mv^2[/tex]

now here we know that

m = 2 kg

v = 15 m/s

now from above formula we know

[tex]KE = \frac{1}{2}(2)(15)^2[/tex]

now we have

[tex]KE = 225 J[/tex]

so kinetic energy of the moving ball is 225 J

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