Respuesta :
Cl⁻ + H₂O(g) = HCl(g) + OH⁻
w - it is percent chloride ions in solid sea salt (as a rule 55%)
m - it is the mass of sea salt
m(Cl⁻)=mw/100
m(Cl⁻)/M(Cl)=V(HCl)/V₀
mw/{100M(Cl)}=V(HCl)/V₀
m=100M(Cl)V(HCl)/{wV₀} (the mass of solid sea salt)
V₀=22.4 L/mol
M(Cl)=35.45 g/mol
for example:
V(HCl)= 1.0 L
w=55%
m=100×35.45×1.0/{55×22.4}=2.88 g
w - it is percent chloride ions in solid sea salt (as a rule 55%)
m - it is the mass of sea salt
m(Cl⁻)=mw/100
m(Cl⁻)/M(Cl)=V(HCl)/V₀
mw/{100M(Cl)}=V(HCl)/V₀
m=100M(Cl)V(HCl)/{wV₀} (the mass of solid sea salt)
V₀=22.4 L/mol
M(Cl)=35.45 g/mol
for example:
V(HCl)= 1.0 L
w=55%
m=100×35.45×1.0/{55×22.4}=2.88 g
First, I would balance the chemical equation.
I would convert the volume of HCl to mol HCl by dividing by the molar volume.
Next, I would use the balanced equation to find out how many moles of the salt are needed to produce the moles of HCl.
Finally, I would multiply by the molar mass of the salt to convert moles to mass.