beba17
beba17
10-06-2017
Mathematics
contestada
algebra 2 help needed
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konrad509
konrad509
10-06-2017
[tex]\det \left[\begin{array}{ccc}3&3&1\\-2&0&-2\\-2&4&-3\end{array}\right] =\\ 3\cdot0\cdot(-3)+3\cdot(-2)\cdot(-2)+1\cdot(-2)\cdot4-1\cdot0\cdot(-2)-3\cdot(-2)\cdot4-\\ -3\cdot(-2)\cdot(3)= 0+12-8-0+24-18=\boxed{10} [/tex]
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