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Write the equation of the line that is perpendicular to y = −14x + 2y = -14x + 2 in slope-intercept form and passes through the point (-4, 3)

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ghanami


Hello:
the equation is : y = ax+b
the slope is a : a×(-14) = -1......( perpendicular to a line with a slope of -14)

because ;the slope of the line : y = −14x + 2


a = 1/14          y=(1/14)x+b
the line that passes through (-4, 3) : 3 = (1/14)(-4)+b
b = 46/4 
 the equation is :  y  = (1/14)x+46/4

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