Answer : Acceleration, [tex]a=-1.525\ m/s^2[/tex].
Explanation :
It is given that,
Initial velocity of skater, u = 24 km/h = 6.66 m/s
Final velocity of skate, v = 13 km/h = 3.61 m/s
Time, t = 2 s
We know that acceleration is defined as the rate of change of velocity.
[tex]a=\dfrac{v-u}{t}[/tex]
So,
[tex]a=\dfrac{3.61\ m/s-6.66 m/s}{2\ s}[/tex]
[tex]a=\dfrac{-3.05}{2}[/tex]
[tex]a=-1.525\ m/s^2[/tex]
The acceleration of the skater is [tex]a=-1.525\ m/s^2[/tex].
