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solve each of the following equations for θ, if 0^°<θ<〖360〗^°. Do not use a calculator or a table:

(a) 2sin⁡θ+√2= 0

Respuesta :

[tex]\bf 2sin(\theta)+\sqrt{2}=0\implies 2sin(\theta)=-\sqrt{2}\implies sin(\theta)=-\cfrac{\sqrt{2}}{2} \\\\\\ \measuredangle \theta=sin^{-1}\left( -\cfrac{\sqrt{2}}{2} \right)[/tex]

check your Unit Circle, that's a well known angle

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