SERIOUS HELP ONLY. (Use Special Right Triangles to Determine the Surface Area of a Regular Pyramid - Geometry).

What is the surface area of this square pyramid?
Round your answer to the nearest tenth.

122.2 yd²

192.8 yd²

244.4 yd²

513.3 yd²

NOTE: Image not drawn to scale.

SERIOUS HELP ONLY Use Special Right Triangles to Determine the Surface Area of a Regular Pyramid Geometry What is the surface area of this square pyramid Round class=

Respuesta :

Answer:

Option B

Step-by-step explanation:

a=side of square=8.4

h = height of the triangle = [tex]1/2(8.4) sin 60 = 2.1\sqrt{3}[/tex]

Each triangle on 4 sides would be equilateral because one angle is 60 and isosceles.

Side of triangle s = 8.4

base area = [tex]a^2 = 70.56\\[/tex]

Area of each equilateral triangle = [tex]\sqrt{3} \frac{s^2}{4} =17.64\sqrt{3}[/tex]

Hence surface area = base area +4(area of each triangle)

[tex]= 70.56+17.64\sqrt{3}(4)\\=192.769\\=192.8[/tex] square yards

Hence option B is right answer

Answer:

192.8 yd²

Step-by-step explanation: