A reaction has the following values. Calculate ΔG.
ΔH = -85.5 kJ/mole
ΔS = 0.133 kJ/mole.K)
Temperature = 110°C
-35 kJ
-64 kJ
-86 kJ
-136 kJ

I attached the formula for calculating Gibbs Free Energy, so you may understand what I'm about to do :)
First we need to convert 110 Celsius to Kelvin.
110 + 273 = 383
Then, we arrange the figures in the correct order.
-85.5 - 383(0.133)
Then we calculate.
-85.5 -383(-133) = -136.43

Your correct answer is -136.

(I'm sorry it took so long for your question to be answered, I only happened to find it by chance.)

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A reaction has the following values. Calculate ΔG. ΔH = -85.5 kJ/mole ΔS = 0.133 kJ/mole.K) Temperature = 110°C -35 kJ -64 kJ -86 kJ -136 kJ

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A reaction has the following values. Calculate ΔG.
ΔH = -85.5 kJ/mole
ΔS = 0.133 kJ/mole.K)
Temperature = 110°C
-35 kJ
-64 kJ
-86 kJ
-136 kJ