Respuesta :
[tex]F=BQv[/tex]
[tex]B= \frac{F}{Qv} [/tex]
[tex]B= \frac{2.2\times10^{-15}}{(1.6\times10^{-19})\times(3.7\times10^4)} [/tex]
B = 0.372T (3sf)
[tex]B= \frac{F}{Qv} [/tex]
[tex]B= \frac{2.2\times10^{-15}}{(1.6\times10^{-19})\times(3.7\times10^4)} [/tex]
B = 0.372T (3sf)
The force experienced by a charged particle in a magnetic field
When a charged particle moves in a magnetic field it experiences a force given by ,
F= qvBsinθ
Here, q= charge on the particle, B = magnetic field strength
v = velocity of the particle
θ = the angle between velocity of the particle and magnetic field
What is magnetic field strength?
Magnetic field strength is the amount of force experienced by a unit north pole when it moves in a magnetic field.
Here,
V= [tex]3 X 10^{4} m/s[/tex]
F = [tex]2.2 X 10^{-15} N[/tex]
θ = 90⁰
Hence, F = qvBsin90 = qvB
So, B = F/ qv
B = [tex]\frac{2.2 X10^{-15} }{(1.6 X 10^{-19}) (3.7 X10^{4} )}[/tex]
B = 0.37T
Hence the strength of magnetic field is 0.37 T.
To know more on force experienced by magnetic field here
https://brainly.com/question/17115312
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