I am confused on how to solve this problem. I did the work and got -0.18. Please explain the process to me!

When a 57-gram piece of aluminum at 100oC is placed in water, it loses 735 calories of heat while cooling to 30oC. Calculate the specific heat capacity of the aluminum

Respuesta :

735 calories = Q
57 grams = mass
SHC = SHC aluminium
temp drop = temp drop.
735 = 57xSHCX70. SHC = 735/(57x70) ... 0. something or other calories per gram per degree celsius.