Words or bytes can be divided into 2s+w addressable units.The block size is 2w words or bytes (cache line width excluding the tag).
How does direct mapping determine block size?
- 2s+w words or bytes are the total number of addressable units.Block size is equal to 2w words or bytes (cache line width excluding tags). There are 2 blocks in main memory (i.e., all the bits that are not in w).
- Fully associative mapping allows every line of the cache that is now open for use to map to a block of main memory.Compared to direct mapping, fully associative mapping is more adaptable because of this.
- The tag is made up of the top 27 address bits.Since the words in the block are located at successive addresses, the complete block only requires a single tag. 16 kB, or 16 * 1024, or 16384 bytes, are available for use.
- Word has 4 bytes, so 16384 bytes divided by 4 bytes each word is 4096 words.Blocks are 4 words in length, hence there are 1024 (210) blocks in every 4096 words.This indicates that the index uses 10 bits.
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