The distance the bullet will miss the target is 1.13 m.
The initial velocity of the bullet = 250 m/s
Distance of the target = 120 m
Calculating the time of motion -
= Distance of the target/ Initial velocity of the bullet
= 120 / 250
= 0.48 s
During this time the bullet is under gravitational pull. It is the force that two objects with mass exert on each other. This force is a fundamental force of nature and is responsible for the attraction between objects with mass. The strength of the gravitational pull between two objects is determined by their masses and the distance between them.
Thus, calculating the distance it will miss the target using the equation -
Y = V₀y + ¹/₂gt²
where;
V₀y is the initial vertical velocity = 0
Therefore, substituting the values -
Y = 0+ ¹/₂gt²
= ¹/₂(9.8)(0.48)²
= = ¹/₂(9.8)(0.2304)
= 1.13
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