A ship travels 12 miles from point A to point B, makes a turn of 112 degrees, and travels 14 miles to point C. If the ship travels directly from point C back to Point A, how many miles will it travel on the last leg of the trip(from point C to point A)? Round your answer to the nearest tenth of a mile.

A)23.4 miles
B)21.6 miles
C)16.2 miles
D)18.8 miles

Respuesta :

use the Cosine Rule:

x^2 = 12^2 + 14^2 - 2*12*14 cos 112

x =  21.6

B is the correcct answer

Answer:

Option B.

Step-by-step explanation:

Given information: AB=12 miles, BC=14 miles and ∠B=112°.

Using given information, we get

[tex]AB=c=12\text{ miles}[/tex]

[tex]BC=a=14\text{ miles}[/tex]

We need to find the value of CA or b.

Cosine formula:

[tex]b^2=a^2+c^-2ac\cos B[/tex]

Substitute a=14, c=12 and B=112.

[tex]b^2=(14)^2+(12)^-2(14)(12)\cos (112)[/tex]

[tex]b^2=196+144-336(-0.3746)[/tex]

[tex]b^2=340+125.8656[/tex]

[tex]b^2=465.8656[/tex]

Taking square root on both sides.

[tex]b=\sqrt{465.8656}[/tex]

[tex]b=21.5839[/tex]

[tex]b\approx 21.6[/tex]

Therefore, the correct option is B.