Step-by-step explanation:
460=100 degrees
therefore a 27 degree distance between speeds
a^2=b^2+c^2-2bc cos A
a^2=9^2+5^2-2(5)(9)cos 27
=45.8
a=6.77 km/h away
I think you wrote 460 wrong also you can't calculate distance if you don't have the time they have travelled for so I gave you a speed.
