Respuesta :

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{-2})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{5}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{ \cfrac{5}{2}}(x-\stackrel{x_1}{(-6)}) \implies y +2= \cfrac{5}{2} (x +6) \\\\\\ y + 2 = \cfrac{5}{2}x + 15\implies y = \cfrac{5}{2}x+13[/tex]