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The platform swing consists of a 200-lb flat plate suspended by four rods of negligible weight. When the swing is at rest, the 150-lb man jumps off the platform when his center of gravity G is 10 ft from the pin at A. This is done with a horizontal velocity of 5 ft/s, measured relative to the swing at the level of G. Determine the angular velocity he imparts to the swing just after jumping off.

Respuesta :

190 rad/s

the angular velocity he imparts to the swing just after jumping off is

190 rad/s.

Wp = 200 lb

a = 10 ft

Wm = 150 lb

b = 11 lb

v = 5 ft/s

c = 4 ft

We know that,

0 = [tex]\frac{-Wm}{g}[/tex](v - ωa)a + [tex]\frac{-Wp}{g}[/tex]([tex]\frac{c^{2} }{12}[/tex] + [tex]b^{2}[/tex]) ω

   = [tex]\frac{150}{9.8}[/tex] (5 - ω(10))10 + [tex]\frac{200}{9.8}[/tex]([tex]\frac{4^{2} }{12}[/tex] + [tex]11^{2}[/tex]) ω

ω = 190 rad/s

What is angular velocity?

  • angular velocity is the speed at which the angle between two bodies changes when an object rotates or revolves around an axis.
  • This displacement is depicted in the image by the angle formed by a line on one body and a line on the other.

What determines angular velocity?

  • As was said in the section on the angular velocity of particles, the angular velocity is determined by the location around which the rotation is being measured.
  • The angular velocities of each of the particles that make up a solid object are therefore distinct.

To learn more about angular velocity visit:

https://brainly.com/question/13649539

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