Respuesta :
The final temperature and the heat transfer in the process 25961 kJ
Solution:
Take CV as the water.
m2 = m1 = m ;
m(u2 − u1) = 1Q2 − 1W2
Process: v = constant until P = P(lift) , then P is constant.
State 1: Two-phase at 100 kPa
u₁ = 417.33+0.5 x 2088.72
= 1461.7 kJ/kg,
V₁ = 0.001043+0.5 x 1.69296
= 0.8475 m³/kg
State 2: v2, P2 <= P(lift)
V2 = 3 x 0.8475=2.5425 m³/kg;
Interpolate:
T2 = 829°C,
u2=3718.76 kJ/kg
=> V2=mv2=25.425 m³
1W2 = Plift(V2-V₁)
=200 × 10 (2.5425 - 0.8475)
= 3390 kJ
1Q2 = m(u2 − u₁) + 1W2
= 10x(3718.76-1461.7)+3390
= 25961 kJ
What is piston?
Among other related systems, pistons are found in reciprocating engines, reciprocating pumps, gas compressors, hydraulic cylinders, and pneumatic cylinders. It is the moving part that is enclosed in a cylinder and sealed off from the gas by piston rings.
To learn more about piston visit:
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