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The point-slope form of the equation of of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x - 12). What
is the standard form of the equation for this line?
O x- 4y = 8
O x-4y=2
O 4x-y= 8
O 4x-y=2

Respuesta :

Heather

Answer: [tex]\frac{1}{4}[/tex]x - y = 2

Step-by-step explanation:

    Standard form is Ax + By = C where A, B, and C, are integers.

   Given:

y - 1 = 1/4(x - 12)

  Distribute:

y - 1 = [tex]\frac{1}{4}[/tex]x - 3

  Add 3 to both sides of the equation:

y  + 2 = [tex]\frac{1}{4}[/tex]x

  Subtract y from both sides of the equation:

2 =  [tex]\frac{1}{4}[/tex]x - y

   Apply the reflexive property:

[tex]\frac{1}{4}[/tex]x - y = 2

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