Respuesta :
There is more variability on glasses of doctor B's dataset than the glasses of doctor B's dataset
Doctor A’s mean absolute deviation on glasses
The dataset for this is given as:
643 634 670 658 636 624 641 655 649 629
Using a statistical calculator, we have:
- Size = 10
- Mean (μ) = 643.9
- Mean Absolute Deviation (MAD) = 11.28
Hence, the mean absolute deviation for Doctor A’s data set on glasses is 11.28
Doctor B’s mean absolute deviation on glasses
The dataset for this is given as:
651 625 622 624 631 621 653 647 646 646
Using a statistical calculator, we have:
- Size = 10
- Mean (μ) = 636.6
- Mean Absolute Deviation (MAD) = 12
Hence, the mean absolute deviation for Doctor B’s data set on glasses is 12
The variation of the two data sets using their mean absolute deviations.
In a dataset, the larger the mean absolute deviations value, the larger the variation.
By comparison, 12 is greater than 11.28
Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor B's dataset
Read more about mean absolute deviation at:
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