Answer:
Disagree
radius = 7 m
diameter = 14 m
Step-by-step explanation:
Formula
[tex]\sf Area\:of\:a\:circle=\pi r^2[/tex]
Given:
Substitute given value into the formula and solve for r:
[tex]\sf \implies \pi r^2=153.88[/tex]
[tex]\sf \implies r^2=\dfrac{153.88}{\pi}[/tex]
[tex]\sf \implies r=\sqrt{\dfrac{153.88}{\pi}}[/tex]
[tex]\sf \implies r=6.998680253[/tex]
Therefore r ≈ 7 m
So I disagree with Nysean, as from my calculations, the approximate radius of the merry-go-round is 7 m.
Diameter = 2r
⇒ diameter of merry-go-round = 2 x 7 = 14m
So Nysean has actually given the approximate measure of the diameter rather than the radius.