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Order the angle measures , , and from least to greatest.
(Note that the figure is not drawn to scale.)

Order the angle measures and from least to greatest Note that the figure is not drawn to scale class=

Respuesta :

Mark the theorem below

  • The angle which measures biggest the opposite side of that angle is biggest.

Here

  • 8<10<12
  • JH<IH<JI

Now

  • <I < <J < <H
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Answer:

least to greatest: ∠I < ∠J < ∠H

Explanation:

angle I:

cosI = [tex]\frac{10^2+12^2-8^2}{2*10*12}[/tex]

I = [tex]cos^{-1} (\frac{3}{4} )[/tex]

I = 41.41°

angle H:

cosH = [tex]\frac{10^2+8^2-12^2}{2*10*8}[/tex]

H = [tex]cos^{-1} (\frac{1}{8} )[/tex]

H = 82.82°

angle J:

cosJ = [tex]\frac{8^2+12^2-10^2}{2*8*12}[/tex]

J = [tex]cos^{-1}(\frac{9}{16} )[/tex]

J = 55.77°

They sum up to 180°, so the steps are correct.

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