Respuesta :
Ur answer is 6 (20+20+20+20+20+20+21+21+21+21+21+21+21+21+21+21+21+21=372) and they need at least 362 hope this helps I'm pretty sure this is right sorry if it's wrong but it seems right to me
Answer:
6
Step-by-step explanation:
It is given that a bike and skate shop rents bikes for $21 per day and pairs of skates for $20 per day.
Let x be the number of pairs of skates.
They rent twice as many bikes as they do pairs of skates.
Number of bikes = 2x
Combined rent of x pairs of skates and 2x bikes is
[tex]Total=21(2x)+20(x)[/tex]
[tex]Total=42x+20x[/tex]
[tex]Total=62x[/tex]
The shop needs to make at least $362 per day from bike and skate rentals combined.
[tex]Total\geq 362[/tex]
[tex]62x\geq 362[/tex]
Divide both sides by 62.
[tex]x\geq \frac{362}{62}[/tex]
[tex]x\geq 5.84[/tex]
The value of x greater than 5.84. So the least integer value of x is 6.
Therefore, the least number of pairs of skates they need to rent each day to make their minimum is 6.