Calculate the distance the marble travels during the first 3.0 seconds. [Show all work, including the equation and substitution with units.]

D = V0t + 0.5at^2
Where d is the distance
V0 is the initial velocity
A is the acceleration
T is time
From the graph a = 4/3 m/s2
D = 0(3) + 0.5( 4/3 m/s2) ( 3 s)^2
D = 6 m