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The length of an aluminium bar of lenth 80cm increase by 1mm on heating. What is the final temperature of the bar if it was initially at temperature 20°C? ( given: coefficient of linear expansion of aluminium = 25×10-6/° C)

Respuesta :

Δl/l = αΔt 
(1×10^-3)/(80×10^-2) = (25×10^-6)×Δt 
Δt = (1×10^-3)/(80×10^-2×25×10^-6) 
Δt=50=t-t0 
t-t0=50 
t-20=50 
t=70°C

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